12v^2+25v-7=0

Solution for 12v^2+25v-7=0 equation:

12v^2+25v-7=0

a = 12; b = 25; c = -7;
Δ = b2-4ac
Δ = 252-4·12·(-7)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-31}{2*12}=\frac{-56}{24}
=-2+1/3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+31}{2*12}=\frac{6}{24}
=1/4
$